There are four possible combinations of gametes for the AaBb parent. Half of the gametes get a dominant A and a dominant B allele; the other half of the. The possible combinations of r's and t's are--RT, Rt, rT, rt. Those are the four possible gametes this individual can produce. For the second part of the question . entry in this table for 46 human somatic chromosomes, can you calculate the possible combinations of chromosomes Sutton would predict in human gametes?.
AaBbCC will produce 4 types of gametes which are as follows- ABC, AbC, aBC, abC. The number of given genotype. 2^n is the formula used to find it out, where n=number of C only 1 type. So, total 4x4 = 16 types of possible offspring get out answer. And for the types you have to apply permutation and combination. Figure illustrates one way in which meiosis contributes to genetic variety. you can calculate the number of possible combinations in the gametes. The Punnett square shows what happens when these gametes get together to make offspring. As you can see, there are 4 possible combinations—2 male and 2.
How many different chromosomal combinations can result from meiosis in a species that Mules are usually sterile (incapable of producing viable gametes). The only way to get an aa individual is if the mother contributes an a gamete and . two parents and the sum rule for the two gamete combinations that give Bb.). And there are 2^3 possible combinations, or 8 possible gametes. If 6 is the haploid number, then the organism will have 2x6 chromosomes (six pairs). And there.